if the length of a rectangle is 4 more than the width and if the perimeter 0of rectangle is 52, what is the width of the rectangle

Answer

The width of the rectangle is 11.

Let's assign a variable to represent the width, so let's say w = width.
Since the length is 4 more than the width, we know the length is w + 4.
The formula for perimeter of a rectangle is P = 2(l + w), so for this rectangle, P = 2(w + w + 4) = 2(2w + 4) = 4w + 8.
We know that the perimeter of the rectangle is 52, so we set the formula equal to 52: 4w + 8 = 52.
Solve for w: 4w = 44, w = 11.