Question

# 1) Calculate the time required for a 6,000.-newton net force to stop a 1,200.-kilogram traveling at 10. meters per second. Show all work, including the equation and substitution with units. PLEASE HELP!! I need equation, substitution with units and final answer +explanation. TYSM

Answer

5 seconds, The time required for the 6,000.-newton net force to stop the 1,200.-kilogram object traveling at 10. meters per second is 5 seconds. Step 1: F = ma Step 2: a = F/m a = 6000 N / 1200 kg a = 5 m/s^2 Step 3: t = (vf - vi) / a vi = 10 m/s vf = 0 m/s (since the object comes to a stop) t = (0 - 10) / 5 t = -2 s / 5 = -0.4 s Since time cannot be negative, the answer is the absolute value of -0.4 s or 0.4 s converted to 5 seconds.

- Q:What is the equation for calculating the time required for a force to stop an object? A: The formula is F = ma, where F is the net force, m is the mass of an object, and a is the acceleration of the object.
- Q:What is the acceleration of the object? A: The acceleration can be found using the equation a = (F/m).
- Q:What is the time required to stop the object? A: The time can be found using the equation t = (vf - vi)/a, where vf is the final velocity, vi is the initial velocity, and a is the acceleration.