Question 10 W An access code consists of 2 letters of the alphabet (A-Z) followed by 6 digits (0-9). How many different access codes are possible if repeats are allowed?

Answer

67,600,000

Determine the number of possibilities for the two letters. They can be any of the 26 letters of the alphabet (A-Z). There are 26 choices for each letter.
Determine the number of possibilities for each of the six digits. They can be any of the 10 digits (0-9). There are 10 choices for each digit.
Multiply the number of possibilities for the letters by the number of possibilities for the digits. 26 * 26 * 10 * 10 * 10 * 10 * 10 * 10 = 67,600,000.