Question

# Question 10 W An access code consists of 2 letters of the alphabet (A-Z) followed by 6 digits (0-9). How many different access codes are possible if repeats are allowed?

Answer

67,600,000

- Determine the number of possibilities for the two letters. They can be any of the 26 letters of the alphabet (A-Z). There are 26 choices for each letter.
- Determine the number of possibilities for each of the six digits. They can be any of the 10 digits (0-9). There are 10 choices for each digit.
- Multiply the number of possibilities for the letters by the number of possibilities for the digits. 26 * 26 * 10 * 10 * 10 * 10 * 10 * 10 = 67,600,000.