Question

# A spring has a spring constant of 13.5N Calculate the elastic potential energy stored in the spring when its extension is 12 cm Use the correct equation from the Physics equation sheet

Answer

0.09288 J

- Q:What is the equation for elastic potential energy? A:The equation for elastic potential energy is EPE = (1/2)kx^2, where EPE = elastic potential energy, k = spring constant, and x = displacement.
- Q:What is the value of k in this problem? A:The value of k in this problem is 13.5N.
- Q:What is the value of x in this problem? A:The value of x in this problem is 0.12m.
- EPE = (1/2)kx^2 A:Substituting the values into the equation, we get EPE = (1/2)(13.5)(0.12)^2 = 0.09288 J.