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A case of 24 cans contains one can that is contaminated. Three cans are to be chosen randomly for testing. A. How many different combinations of three cans could be selected?.



  • Q:What is the formula to calculate the number of combinations? A:The formula to calculate the number of combinations is nCk = n!/(k!(n-k)!), where n is the total number of items and k is the number of items to choose.
  • Q:What is the value of n and k in this problem? A:n = 24, k = 3.
  • nCk = 24C3 = 24!/(3!(24-3)!) = 2,024.