A case of 24 cans contains one can that is contaminated. Three cans are to be chosen randomly for testing. A. How many different combinations of three cans could be selected?.

Answer

2,024

Q:What is the formula to calculate the number of combinations? A:The formula to calculate the number of combinations is nCk = n!/(k!(n-k)!), where n is the total number of items and k is the number of items to choose.
Q:What is the value of n and k in this problem? A:n = 24, k = 3.
nCk = 24C3 = 24!/(3!(24-3)!) = 2,024.