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Question

How many atoms are present in 6 moles of Al(s) in the following reaction? 2Al(s) + 3 CuSO+ (aq) - › Al2 (SO4)3 (aq) + 3 Cu(s)

Answer

3.6 × 10²⁴ atoms

This is a stoichiometry problem. The balanced chemical equation shows that 2 moles of Al react with the formation of 3 moles of Cu. Thus, we can set up a proportion to find the number of atoms of Al present in 6 moles of Al. 2 mol Al / 2 mol Al atoms * 6 mol Al / 1 = 6 mol * 6.022 x 10²³atoms/mol = 3.6 × 10²⁴ atoms. Therefore, 6 moles of Al contains 3.6 × 10²⁴ atoms of Al.