Question

# What is the magnitude of the force of the elevator floor on a person weighing 0.70 kn, while the elevator has an upward acceleration of 1.5 m/s²?

Answer

10.07 kN (kilonewtons)

The force acting on the person equals the sum of their weight and the force needed to provide the acceleration. F(floor) = F(person) + ma. F(floor) = (0.70 kn)(9.81 m/s²) + (0.70 kn)(1.5 m/s²) = 6.867 + 1.200 = 8.067 kN ≈ 10.07 kN (rounded to two decimals).