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Consider the system y' + 4y = f(t), where f(t) = 4e^-t a. Solve the ODE with y(0) = 0 using the technique of integrating factors: (Do not use Laplace transforms ) y(t) = ...?b. Find the transfer function of the system: H(s) = ...?c. Find the impulse response of the system: h(t) = L^-1 [H](t) d. Evaluate the convolution integral (h*f)(t) , and compare the resulting function with the solution obtained in part (a): (h*f)(t) = ∫ dw =

Answer

"The convolution integral produces a solution equivalent to that derived in part (a). To solve the ODE with y(0) = 0 using integrating factors, we multiply both sides of the equation by e^4t, resulting in e^4t y' + 4e^4t y = 4e^-te^4t. By integrating both sides, we get ∫ (e^4t y' + 4e^4t y) dt = ∫ 4e^-te^4t dt. Thus, e^4t y = ∫ 4e^-te^4t dt + C. Since y(0) = 0, C is equal to 0, and we obtain the solution y = 1/4 ∫ 4e^-te^4t dt by integrating via parts. Consequently, y(t) = 1/4 [te^-t + 4/3 e^-t]. The system's transfer function is H(s) = Y(s)/F(s) = 1/4s/(s+4), and the impulse response is h(t) = L^-1[H(s)] = 1/4e^-t. Lastly, evaluating the convolution integral (h*f)(t) shows us that (h*f)(t) = ∫ h(t-w)f(w)dw = ∫ 1/4e^-(t-w) 4e^-w dw = 1/4 ∫ 4e^-(t+w) dw = 1/4 [te^-t + 4/3 e^-t]." To learn more about convolution integrals, check out brainly.com/question/28167424 #SPJ4.