# One way to control avalanches is to send explosive charges to key areas on mountain slopes to trigger small avalanches before larger ones can build up. Norway, for instance, uses solar- powered launchers that fire pre-timed charges. Your launcher fires charges at an angle of 70 degrees from the horizontal and a speed of 200 m/s. If you fire a charge and it travels a horizontal distance of 300 m away from you, how high up the slope will it strike?.

Using uniform motion, the projectile will strike at a height of 730.62 meters up the slope. It is essential to have a thorough understanding of uniform motion to solve this problem. Uniform motion entails the motion of an object under acceleration and follows the formula vt = vo + a . t, vt² = vo² + 2a . s, and s = vo . t + 1/2 . a . t², where vt denotes final velocity, vo refers to initial velocity, a is acceleration, t is time, and s is displacement. From the above question, we learn that θ = 70⁰, vi = 200 m/s, and x = 300 m. To determine the initial velocity in the x and y axes, we use the formulae: vx = vi cosθ = 68.40 m/s and vy = vi sinθ = 187.94 m/s. The time taken to reach 300 m is given by: t = 4.39 seconds, while the time taken to reach the maximum height is t = 19.18 seconds, using the equation vt = vo + a . t and vy = gt, respectively. Since the projectile is rising to the maximum height, we use h = vy . t - 1/2 . g . t² and obtain the maximum height or h = 730.62 m. For further insights into uniform motion, visit: brainly.com/question/28040370 #SPJ4.