# g the eskimo pushes the same 50.0-kg sled over level ground with a force of 2.30 102 n exerted horizontally, moving it a distance of 5.55 m over new terrain. if the net work done on the sled is 2.50 102 j find the coefficient of kinetic friction.

Alright class, let's discuss the coefficient of kinetic friction, which we've determined to be ∪ = 3.699. Now, what is kinetic energy? In the field of physics, kinetic energy refers to the energy an object possesses due to its motion. Specifically, it reflects the amount of work required to move a body of mass from a state of rest to a given velocity. This kinetic energy is maintained by the object until its velocity changes. Now, let's consider these numbers: we have a mass of m = 50 kg, a force of 2.30 x 10^2 N, a distance of 5.55 m, and a work done of 2.50 x 10^2 J. Utilizing the work-energy principle, which states that F x d - ∪ x m x d = work done, we can calculate the coefficient of friction (∪). Thus, 230 x 5.55 - ∪ x 50 x 5.55 = 250. Simplifying, we get 1276.5 - ∪ x 277.5 = 250. Solving for ∪, we find that ∪ = 3.699. So, our final answer is that the coefficient of kinetic friction is ∪ = 3.699. If you want to continue learning about kinetic energy, I suggest clicking on the link provided: brainly.com/question/25959744 #SPJ4.