Question

# Convert the equation into Standard Form. x^2 + y^2 + 10x - 12y+45 = 0

Answer

What is the equation of the circle that has a center at (5, -6) and a radius of 3 units? Step-by-step explanation: First, we use the formula for the equation of a circle: (x - h)^2 + (y - k)^2 = r^2 where (h, k) is the center of the circle and r is its radius. In this case, we are given that the center is (5, -6) and the radius is 3, so we substitute these values into the formula: (x - 5)^2 + (y + 6)^2 = 3^2 Simplifying the equation, we get: (x - 5)^2 + (y + 6)^2 = 9 Therefore, the equation of the circle with center at (5, -6) and radius 3 is (x - 5)^2 + (y + 6)^2 = 9.