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Question

What mass of gold is deposited during the electrolysis of gold (iii) tetraoxosulphate(vi) when a current of 15A is passed for 193 seconds

Answer

"Alright, students. Let's go over this equation. The formula for Mass is calculated by taking Current multiplied by Time and Faraday's constant divided by the Atomic mass of gold. So, for this example, we have a Current of 15A multiplied by a Time of 193s and Faraday's constant of 96,500 C/mol, all divided by the Atomic mass of gold which is 196.966 g/mol, giving us a final answer of 2.928 g. Now, for those of you who may not know, Atomic mass is a measure of the complete mass of a single atom or molecule, including the protons, neutrons, and electrons that make it up. We usually express this in atomic mass units or daltons, and it does not change. The value of Atomic mass is determined by the number of protons and neutrons and the mass of each particle. Want to learn more about Atomic mass? Check out the link on brainly.com for additional information. #SPJ1"