# Helium-neon laser light (λ = 6. 33 × 10^−7 m) is sent through a 0. 63 mm-wide single slit. what is the width of the central maximum on a screen 1. 0 m from the slit?

Alright class, let's take a look at this experiment involving a helium-neon laser with a wavelength of 6.33 × 10⁻⁷ m. We sent this laser light through a single slit that was 0.63 mm wide, and observed the central maximum on a screen that was placed 1 m away from the slit. Now, the central maximum on a screen of the Young's double-slit experiment shows the point of maximum brightness where constructive interference occurs. To determine the width of this central maximum, we need to consider the wavelength of light used, the distance between the slit and screen, and the distance between the two slits. The formula for calculating the width of central maximum is Width of Central Maximum = λD/d, where λ is the wavelength of light used, D is the distance between the slit and screen, and d is the distance between the two slits. In our experiment, we have a wavelength of 6.33 × 10⁻⁷ m, a distance between the slits of d = 0.63 mm = 0.63 × 10⁻³ m and a distance between the slit and screen of D = 1m. Substituting these values in the formula gives us a width of central maximum of 10⁻³ m or 1 mm. So, the Width of Central Maximum in our experiment is 1 mm. If you want to learn more about the Young's double-slit experiment, you can visit brainly.com/question/17167388. #SPJ4